232 스택을 이용한 큐 구현

문제

Implement a first in first out (FIFO) queue using only two stacks. The implemented queue should support all the functions of a normal queue (push, peek, pop, and empty). Implement the MyQueue class:

조건

예제

Input
["MyQueue", "push", "push", "peek", "pop", "empty"]
[[], [1], [2], [], [], []]
Output
[null, null, null, 1, 1, false]

Explanation
MyQueue myQueue = new MyQueue();
myQueue.push(1); // queue is: [1]
myQueue.push(2); // queue is: [1, 2] (leftmost is front of the queue)
myQueue.peek(); // return 1
myQueue.pop(); // return 1, queue is [2]
myQueue.empty(); // return false

해결할 이슈?

1st

생각

코드

class MyQueue:

    def __init__(self):
        """
        Initialize your data structure here.
        """
        self.stack = []
        self._lenth = 0

    def push(self, x: int) -> None:
        """
        Push element x to the back of queue.
        """
        self.stack.append(x)
        self._lenth += 1
        

    def pop(self) -> int:
        """
        Removes the element from in front of queue and returns that element.
        """
        if self.empty():
           return None
        self._lenth -= 1

        return self.stack.pop(0)
        

    def peek(self) -> int:
        """
        Get the front element.
        """
        if self.empty():
           return None
        
        return self.stack[0]
        

    def empty(self) -> bool:
        """
        Returns whether the queue is empty.
        """
        return self._lenth == 0

결과

Runtime: 32 ms, faster than 55.71% of Python3 online submissions for Implement Queue using Stacks. Memory Usage: 14.5 MB, less than 12.11% of Python3 online submissions for Implement Queue using Stacks.